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Thus Dilbert is credited with inventing the “[[Dilbert definition]]” in which ''RE<sub>n</sub> == r<sub>n</sub>''.<ref>RE = Referential expression; ''r'' = Referent</ref> In this case, the thing being defined (the “referent”) and the label defining it (the “referring expression”) are identical, as illustrated in the following example: | Thus Dilbert is credited with inventing the “[[Dilbert definition]]” in which ''RE<sub>n</sub> == r<sub>n</sub>''.<ref>RE = Referential expression; ''r'' = Referent</ref> In this case, the thing being defined (the “referent”) and the label defining it (the “referring expression”) are identical, as illustrated in the following example: | ||
{{quote|An insured person (the “'''insured person'''”) may cancel (“'''cancel'''”) a policy (the “'''policy'''”) by providing us as insurer (“'''us'''” or the “'''insurer'''”) a written notice (the “'''written notice'''”) of the cancellation (the “'''cancellation'''”)}} | {{quote|An insured person (the “'''insured person'''”) may cancel (“'''cancel'''”) a policy (the “'''policy'''”) by providing us as insurer (“'''us'''” or the “'''insurer'''”) a written notice (the “'''written notice'''”) of the cancellation (the “'''cancellation'''”).}} | ||
Academic debate rages to this day as to whether a [[Dilbert definition]] qualifies as an unusually stable type of [[Biggs hoson]], or whether it simply has null semantic content. | Academic debate rages to this day as to whether a [[Dilbert definition]] qualifies as an unusually stable type of [[Biggs hoson]], or whether it simply has null semantic content. |